A body of mass 2 kg begins to move under the action of a time dependent force given by F= (6t i+6t2 j ) N. The power developed by the force at the time t is given by:
- (3t3+6t5 ) W
- (9t5+6t3 ) W
- (6t4+9t5 ) W
- (9t3+6t5 ) W
Answer
(4) (9t3+6t5 ) W
Solution
a= Fm=3t i+3t2 j
the body starts from rest: v= 0t a dt= 3t22 i+t3 j
P= F v=6t 3t22+6t2 t3
P= (9t3+6t5 ) W
Answer: (4)