A simple pendulum of length 1 m has a wooden bob of mass 1 kg. It is struck by a bullet of mass 10-2 kg moving with a speed of 2 102 ms-1. The bullet gets embedded into the bob. The height to which the bob rises before swinging back is : (use g=10 m/s2)
- 0.20 m
- 0.40 m
- 0.30 m
- 0.35 m
Answer
(1) 0.20 m
Solution
Collision (momentum conserved): mu=(M+m)v
v= 10-2 2001.01 2 m/s
after the collision mechanical energy is conserved: 12v2=gh
h= v22g= (2)22 10
h=0.20 m
Answer: (1)