A solution of copper sulphate is electrolysed for 10 minutes with a current of 1.5 amperes. The mass of copper deposited at cathode is : (Given : Molar mass of Cu = 63 g mol-1; 1F = 96487 C mol-1)
- 0.2938 g
- 0.5876 g
- 2.4036 g
- 1.7018 g
Answer
(1) 0.2938 g
Solution
Q = I × t = 1.5 A × (10 × 60) s = 900 C
Cu2+ + 2e- Cu ⇒ 2 F (2 × 96487 C) deposit 1 mol (63 g) Cu
∴ Mass of Cu = 63 9002 96487 = 0.2938 g
Answer: (1)