The standard electrode potential (E ) for the half-cell reaction Fe3+ + e- Fe2+ at 298 K is (Given : E ( Fe3+/Fe) = -0.04 V and E ( Fe2+/Fe) = -0.44 V at 298 K)
- +0.92 V
- +0.40 V
- +0.76 V
- -0.48 V
Answer
(3) +0.76 V
Solution
Using G = -nFE :
1. Fe3+ + 3e- Fe; G1 = -3F(-0.04) = +0.12F
2. Fe2+ + 2e- Fe; G2 = -2F(-0.44) = +0.88F
Subtracting (2) from (1) gives:
Fe3+ + e- Fe2+
G3 = G1 - G2 = 0.12F - 0.88F = -0.76F
Since G3 = -1FE 3:
-1FE 3 = -0.76F E 3 = +0.76 V.
Answer: (3)