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Coordination Compounds · Question 39

JEE Main 2025 (Online) 7th April Evening ShiftMatchingMedium📈 Topic in 13% papers+4−1
1

Match List - I with List - II. Choose the correct answer from the options given below :

  1. A-I, B-III, C-II, D-IV
  2. A-II, B-III, C-IV, D-I
  3. A-I, B-IV, C-IV, D-III
  4. A-III, B-I, C-II, D-IV

Answer

(3) A-I, B-IV, C-IV, D-III

Solution

As per Werner's theory, primary valency = oxidation state of the central metal and secondary valency = coordination number.

(A) [Co(en)2Cl2]Cl: x + 0 + 2(-1) = +1 x = +3; donor atoms = 2 2 (en) + 2 (Cl) = 6 (3, 6) → I

(B) [Pt(NH3)2Cl(NO2)]: x + 0 - 1 - 1 = 0 x = +2; four monodentate ligands, CN = 4 (2, 4) → IV

(C) Hg[Co(SCN)4]: Hg2+ [Co(SCN)4]2-; x + 4(-1) = -2 x = +2; CN = 4 (2, 4) → IV

(D) [Mg(EDTA)]2-: EDTA4- x - 4 = -2 x = +2; EDTA is hexadentate, CN = 6 (2, 6) → III

A-I, B-IV, C-IV, D-III

Answer: (3)

JEE Main 2025 (Online) 7th April Evening Shift

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2

The number of unpaired electrons responsible for the paramagnetic nature of the following complex species are respectively : [Fe(CN)6]3-, [FeF6]3-, [CoF6]3-, [Mn(CN)6]3-

  1. 1, 5, 4, 2
  2. 1, 4, 4, 2
  3. 1, 5, 5, 2
  4. 1, 1, 4, 2
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3

The number of paramagnetic metal complex species among [Co(NH3)6]3+, [Co(C2O4)3]3-, [MnCl6]3-, [Mn(CN)6]3-, [CoF6]3-, [Fe(CN)6]3- and [FeF6]3- with same number of unpaired electrons is .

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4

Which one of the following complexes will have o = 0 and = 5.96 B.M.?

  1. [FeF6]4-
  2. [Mn(SCN)6]4-
  3. [Co(NH3)6]3+
  4. [Fe(CN)6]4-
JEE Main 2025 (Online) 4th April Morning Shift
5

Number of stereoisomers possible for the complexes, [CrCl3(py)3] and [CrCl2(ox)2]3- are respectively (py = pyridine, ox = oxalate)

  1. 3 & 3
  2. 2 & 3
  3. 1 & 2
  4. 2 & 2
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6

'X' is the number of electrons in t2g orbitals of the most stable complex ion among [Fe(NH3)6]3+, [FeCl6]3-, [Fe(C2O4)3]3- and [Fe(H2O)6]3+. The nature of oxide of vanadium of the type V2OX is :

  1. Amphoteric
  2. Acidic
  3. Basic
  4. Neutral
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7

The correct order of [FeF6]3-, [CoF6]3-, [Ni(CO)4] and [Ni(CN)4]2- complex species based on the number of unpaired electrons present is:

  1. [CoF6]3- > [FeF6]3- > [Ni(CO)4] > [Ni(CN)4]2-
  2. [FeF6]3- > [CoF6]3- > [Ni(CN)4]2- > [Ni(CO)4]
  3. [FeF6]3- > [CoF6]3- > [Ni(CN)4]2- = [Ni(CO)4]
  4. [Ni(CN)4]2- > [FeF6]3- > [CoF6]3- > [Ni(CO)4]
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8

A metal complex with a formula MCl4 3NH3 is involved in sp3d2 hybridisation. It upon reaction with excess of AgNO3 solution gives 'x' moles of AgCl. Consider 'x' is equal to the number of lone pairs of electrons present in the central atom of BrF5. Then the number of geometrical isomers exhibited by the complex is .

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9

The correct order of the complexes [Co(NH3)5(H2O)]3+ (A), [Co(NH3)6]3+ (B), [Co(CN)6]3- (C) and [CoCl(NH3)5]2+ (D) in terms of wavelength of light absorbed is

  1. D > C > B > A
  2. C > B > A > D
  3. D > A > B > C
  4. C > B > D > A
JEE Main 2025 (Online) 3rd April Morning Shift
10

The number of optical isomers exhibited by the iron complex (A) obtained from the following reaction is . FeCl3 + KOH + H2C2O4 A

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11

Identify the diamagnetic octahedral complex ions from below ; Choose the correct answer from the options given below:

  1. B and C Only
  2. A and C Only
  3. B and D Only
  4. A and D Only
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