PYQSide ExamsMy practice

Coordination Compounds · Question 41

JEE Main 2025 (Online) 7th April Evening ShiftNumericalMedium📈 Topic in 42% papers+4
1

The number of paramagnetic metal complex species among [Co(NH3)6]3+, [Co(C2O4)3]3-, [MnCl6]3-, [Mn(CN)6]3-, [CoF6]3-, [Fe(CN)6]3- and [FeF6]3- with same number of unpaired electrons is .

Answer

2

Solution

[Co(NH3)6]3+: Co3+, 3d6, strong field, t2g6eg0 0 unpaired (diamagnetic)

[Co(C2O4)3]3-: Co3+, 3d6, low spin t2g6eg0 0 unpaired (diamagnetic)

[MnCl6]3-: Mn3+, 3d4, weak field, t2g3eg1 4 unpaired

[Mn(CN)6]3-: Mn3+, 3d4, strong field, t2g4eg0 2 unpaired

[CoF6]3-: Co3+, 3d6, weak field, t2g4eg2 4 unpaired

[Fe(CN)6]3-: Fe3+, 3d5, strong field, t2g5eg0 1 unpaired

[FeF6]3-: Fe3+, 3d5, weak field, t2g3eg2 5 unpaired

Paramagnetic species have 4, 2, 4, 1 and 5 unpaired electrons. Only [MnCl6]3- and [CoF6]3- have the same number (4).

Answer: 2

JEE Main 2025 (Online) 7th April Evening Shift

Keep practising — Coordination Compounds

2

Which one of the following complexes will have o = 0 and = 5.96 B.M.?

  1. [FeF6]4-
  2. [Mn(SCN)6]4-
  3. [Co(NH3)6]3+
  4. [Fe(CN)6]4-
JEE Main 2025 (Online) 4th April Morning Shift
3

Number of stereoisomers possible for the complexes, [CrCl3(py)3] and [CrCl2(ox)2]3- are respectively (py = pyridine, ox = oxalate)

  1. 3 & 3
  2. 2 & 3
  3. 1 & 2
  4. 2 & 2
JEE Main 2025 (Online) 4th April Morning Shift
4

'X' is the number of electrons in t2g orbitals of the most stable complex ion among [Fe(NH3)6]3+, [FeCl6]3-, [Fe(C2O4)3]3- and [Fe(H2O)6]3+. The nature of oxide of vanadium of the type V2OX is :

  1. Amphoteric
  2. Acidic
  3. Basic
  4. Neutral
JEE Main 2025 (Online) 4th April Evening Shift
5

The correct order of [FeF6]3-, [CoF6]3-, [Ni(CO)4] and [Ni(CN)4]2- complex species based on the number of unpaired electrons present is:

  1. [CoF6]3- > [FeF6]3- > [Ni(CO)4] > [Ni(CN)4]2-
  2. [FeF6]3- > [CoF6]3- > [Ni(CN)4]2- > [Ni(CO)4]
  3. [FeF6]3- > [CoF6]3- > [Ni(CN)4]2- = [Ni(CO)4]
  4. [Ni(CN)4]2- > [FeF6]3- > [CoF6]3- > [Ni(CO)4]
JEE Main 2025 (Online) 4th April Evening Shift
6

A metal complex with a formula MCl4 3NH3 is involved in sp3d2 hybridisation. It upon reaction with excess of AgNO3 solution gives 'x' moles of AgCl. Consider 'x' is equal to the number of lone pairs of electrons present in the central atom of BrF5. Then the number of geometrical isomers exhibited by the complex is .

JEE Main 2025 (Online) 4th April Evening Shift
7

The correct order of the complexes [Co(NH3)5(H2O)]3+ (A), [Co(NH3)6]3+ (B), [Co(CN)6]3- (C) and [CoCl(NH3)5]2+ (D) in terms of wavelength of light absorbed is

  1. D > C > B > A
  2. C > B > A > D
  3. D > A > B > C
  4. C > B > D > A
JEE Main 2025 (Online) 3rd April Morning Shift
8

The number of optical isomers exhibited by the iron complex (A) obtained from the following reaction is . FeCl3 + KOH + H2C2O4 A

JEE Main 2025 (Online) 3rd April Morning Shift
9

Identify the diamagnetic octahedral complex ions from below ; Choose the correct answer from the options given below:

  1. B and C Only
  2. A and C Only
  3. B and D Only
  4. A and D Only
JEE Main 2025 (Online) 3rd April Evening Shift
10

Given below are two statements : In the light of the above statements, choose the most appropriate answer from the options given below :

  1. Both Statement I and Statement II are incorrect
  2. Statement I is correct but Statement II is incorrect
  3. Statement I is incorrect but Statement II is correct
  4. Both Statement I and Statement II are correct
JEE Main 2025 (Online) 2nd April Morning Shift
11

A transition metal (M) among Mn, Cr, Co and Fe has the highest standard electrode potential (M3+/M2+). It forms a metal complex of the type [M(CN)6]4-. The number of electrons present in the eg orbital of the complex is .

JEE Main 2025 (Online) 2nd April Morning Shift

All Coordination Compounds PYQs →

PDFDownload Coordination Compounds PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇
All JEE Main Chemistry chapters