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Coordination Compounds · Question 44

JEE Main 2025 (Online) 4th April Evening ShiftMCQHard📈 Topic in 55% papers+4−1
1

'X' is the number of electrons in t2g orbitals of the most stable complex ion among [Fe(NH3)6]3+, [FeCl6]3-, [Fe(C2O4)3]3- and [Fe(H2O)6]3+. The nature of oxide of vanadium of the type V2OX is :

  1. Amphoteric
  2. Acidic
  3. Basic
  4. Neutral

Answer

(1) Amphoteric

Solution

All four complexes contain Fe3+ (3d5).

C2O42- is a bidentate (chelating) ligand: each forms a five-membered chelate ring chelate effect [Fe(C2O4)3]3- is the most stable complex.

With the chelating oxalate ligand (stronger field than Cl- and H2O), the five d electrons are taken as paired in the t2g set:

Fe3+: t2g5 eg0 X = 5

Oxide = V2O5. As per NCERT, V2O5 is amphoteric (though mainly acidic); it reacts with both acids and alkalis.

Answer: (1)

JEE Main 2025 (Online) 4th April Evening Shift

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2

The correct order of [FeF6]3-, [CoF6]3-, [Ni(CO)4] and [Ni(CN)4]2- complex species based on the number of unpaired electrons present is:

  1. [CoF6]3- > [FeF6]3- > [Ni(CO)4] > [Ni(CN)4]2-
  2. [FeF6]3- > [CoF6]3- > [Ni(CN)4]2- > [Ni(CO)4]
  3. [FeF6]3- > [CoF6]3- > [Ni(CN)4]2- = [Ni(CO)4]
  4. [Ni(CN)4]2- > [FeF6]3- > [CoF6]3- > [Ni(CO)4]
JEE Main 2025 (Online) 4th April Evening Shift
3

A metal complex with a formula MCl4 3NH3 is involved in sp3d2 hybridisation. It upon reaction with excess of AgNO3 solution gives 'x' moles of AgCl. Consider 'x' is equal to the number of lone pairs of electrons present in the central atom of BrF5. Then the number of geometrical isomers exhibited by the complex is .

JEE Main 2025 (Online) 4th April Evening Shift
4

The correct order of the complexes [Co(NH3)5(H2O)]3+ (A), [Co(NH3)6]3+ (B), [Co(CN)6]3- (C) and [CoCl(NH3)5]2+ (D) in terms of wavelength of light absorbed is

  1. D > C > B > A
  2. C > B > A > D
  3. D > A > B > C
  4. C > B > D > A
JEE Main 2025 (Online) 3rd April Morning Shift
5

The number of optical isomers exhibited by the iron complex (A) obtained from the following reaction is . FeCl3 + KOH + H2C2O4 A

JEE Main 2025 (Online) 3rd April Morning Shift
6

Identify the diamagnetic octahedral complex ions from below ; Choose the correct answer from the options given below:

  1. B and C Only
  2. A and C Only
  3. B and D Only
  4. A and D Only
JEE Main 2025 (Online) 3rd April Evening Shift
7

Given below are two statements : In the light of the above statements, choose the most appropriate answer from the options given below :

  1. Both Statement I and Statement II are incorrect
  2. Statement I is correct but Statement II is incorrect
  3. Statement I is incorrect but Statement II is correct
  4. Both Statement I and Statement II are correct
JEE Main 2025 (Online) 2nd April Morning Shift
8

A transition metal (M) among Mn, Cr, Co and Fe has the highest standard electrode potential (M3+/M2+). It forms a metal complex of the type [M(CN)6]4-. The number of electrons present in the eg orbital of the complex is .

JEE Main 2025 (Online) 2nd April Morning Shift
9

The type of hybridization and the magnetic property of [MnCl6]3- are,

  1. sp3d2, paramagnetic with four unpaired electrons.
  2. d2sp3, paramagnetic with four unpaired electrons.
  3. sp3d2, paramagnetic with two unpaired electrons.
  4. d2sp3, paramagnetic with two unpaired electrons.
JEE Main 2025 (Online) 2nd April Evening Shift
10

The d-orbital electronic configuration of the complex among [Co(en)3]3+, [CoF6]3-, [Mn(H2O)6]2+ and [Zn(H2O)6]2+ that has the highest CFSE is:

  1. t2g6eg0
  2. t2g3eg2
  3. t2g4eg2
  4. t2g6eg4
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11

The correct increasing order of stability of the complexes based on 0 value is : I. [Mn(CN)6]3- II. [Co(CN)6]4- III. [Fe(CN)6]4- IV. [Fe(CN)6]3-

  1. I < II < IV < III
  2. IV < III < II < I
  3. III < II < IV < I
  4. II < III < I < IV
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