Coordination Compounds · Question 45

A metal complex with a formula MCl4 3NH3 is involved in sp3d2 hybridisation. It upon reaction with excess of AgNO3 solution gives 'x' moles of AgCl. Consider 'x' is equal to the number of lone pairs of electrons present in the central atom of BrF5. Then the number of geometrical isomers exhibited by the complex is .

The correct order of the complexes [Co(NH3)5(H2O)]3+ (A), [Co(NH3)6]3+ (B), [Co(CN)6]3- (C) and [CoCl(NH3)5]2+ (D) in terms of wavelength of light absorbed is

1. D > C > B > A
2. C > B > A > D
3. D > A > B > C
4. C > B > D > A

The number of optical isomers exhibited by the iron complex (A) obtained from the following reaction is . FeCl3 + KOH + H2C2O4 A

Identify the diamagnetic octahedral complex ions from below ; Choose the correct answer from the options given below:

1. B and C Only
2. A and C Only
3. B and D Only
4. A and D Only

Given below are two statements : In the light of the above statements, choose the most appropriate answer from the options given below :

1. Both Statement I and Statement II are incorrect
2. Statement I is correct but Statement II is incorrect
3. Statement I is incorrect but Statement II is correct
4. Both Statement I and Statement II are correct

A transition metal (M) among Mn, Cr, Co and Fe has the highest standard electrode potential (M3+/M2+). It forms a metal complex of the type [M(CN)6]4-. The number of electrons present in the eg orbital of the complex is .

The type of hybridization and the magnetic property of [MnCl6]3- are,

1. sp3d2, paramagnetic with four unpaired electrons.
2. d2sp3, paramagnetic with four unpaired electrons.
3. sp3d2, paramagnetic with two unpaired electrons.
4. d2sp3, paramagnetic with two unpaired electrons.

The d-orbital electronic configuration of the complex among [Co(en)3]3+, [CoF6]3-, [Mn(H2O)6]2+ and [Zn(H2O)6]2+ that has the highest CFSE is:

1. t2g6eg0
2. t2g3eg2
3. t2g4eg2
4. t2g6eg4

The correct increasing order of stability of the complexes based on 0 value is : I. [Mn(CN)6]3- II. [Co(CN)6]4- III. [Fe(CN)6]4- IV. [Fe(CN)6]3-

1. I < II < IV < III
2. IV < III < II < I
3. III < II < IV < I
4. II < III < I < IV

Match List - I with List - II. Choose the correct answer from the options given below :

1. (A)-(III), (B)-(I), (C)-(I), (D)-(IV)
2. (A)-(III), (B)-(II), (C)-(III), (D)-(IV)
3. (A)-(IV), (B)-(II), (C)-(I), (D)-(III)
4. (A)-(IV), (B)-(I), (C)-(II), (D)-(III)