The period of oscillation of a mass M suspended from a spring of negligible mass is T. If along with it another mass M is also suspended, the period of oscillation will now be
- T
- T 2
- 2T
- 2T
Answer
(4) 2T
Solution
For a spring–mass system: T = 2 Mk, so T M
Mass becomes 2M:
T' = 2 2Mk = 2T
Answer: (4)