A simple pendulum performs simple harmonic motion about x = 0 with an amplitude a and time period T. The speed of the pendulum at x = a/2 will be
- aT
- 3 2 aT
- a 3T
- a 32T
Answer
(3) a 3T
Solution
In SHM, v = a2 - x2 with = 2 T
At x = a2:
v = 2 T a2 - a24
v = 2 T 3a2
v = a 3T
Answer: (3)