Let the mean and variance of 8 numbers −10, −7, −1, x, y, 9, 2, 16 be 72 and 2934, respectively. Then the mean of 4 numbers x, y, x + y + 1, |x − y| is :
- 11
- 9
- 10
- 12
Answer
(1) 11
Solution
Mean: -10 - 7 - 1 + x + y + 9 + 2 + 168 = 72
9 + x + y = 28 x + y = 19
Variance: xi28 - ( 72 )2 = 2934
xi2 = 8 3424 = 684
100 + 49 + 1 + x2 + y2 + 81 + 4 + 256 = 684
x2 + y2 = 193
(x - y)2 = 2(x2 + y2) - (x + y)2 = 386 - 361 = 25
|x - y| = 5
Required mean = (x + y) + (x + y + 1) + |x - y|4 = 19 + 20 + 54 = 11
Answer: (1)