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Structure of Atom · Question 53

AIPMT 2004MCQEasy📈 Topic in 0% papers+4−1
1

The radioactive isotope 6027Co which is used in the treatment of cancer can be made by (n, p) reaction. For this reaction the target nucleus is

  1. 5928Ni
  2. 5927Co
  3. 6028Ni
  4. 6027Co

Answer

(3) 6028Ni

Solution

In an (n, p) reaction the target nucleus absorbs a neutron 10n and emits a proton 11H:

AZX + 10n 6027Co + 11H

Mass numbers: A + 1 = 60 + 1, so A = 60

Atomic numbers: Z + 0 = 27 + 1, so Z = 28 (nickel)

Target nucleus = 6028Ni

Answer: (3)

AIPMT 2004

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2

The value of Planck's constant is 6.63 10-34 J s. The velocity of light is 3.0 108 m s-1. Which value is closest to the wavelength in nanometers of a quantum of light with frequency of 8 1015 s-1 ?

  1. 2 10-25
  2. 5 10-18
  3. 4 101
  4. 3 107
AIPMT 2003
3

In hydrogen atom, energy of first excited state is -3.4 eV. Then find out K.E. of same orbit of hydrogen atom

  1. +3.4 eV
  2. +6.8 eV
  3. -13.6 eV
  4. +13.6 eV
AIPMT 2002
4

23592U, nucleus absorbs a neutron and disintegrates into 13954Xe, 9438Sr and x so, what will be product x?

  1. 3-neutrons
  2. 2-neutrons
  3. -particle
  4. -particle
AIPMT 2002
5

The following quantum numbers are possible for how many orbitals : n = 3, l = 2, m = +2 ?

  1. 1
  2. 2
  3. 3
  4. 4
AIPMT 2001
6

If a abX species emits first a positron, then two and two particles and in the last, one is also emitted and gets converted to cdY species. So correct relation is

  1. c = a - 12, d = b - 5
  2. c = a - 5, d = b - 1
  3. c = a - 6, d = b - 0
  4. c = a - 4, d = b - 2
AIPMT 2001
7

For given energy, E = 3.03 10-19 Joules corresponding wavelength is (h = 6.626 10-34 J sec, c = 3 108 m/sec)

  1. 65.6 nm
  2. 6.56 nm
  3. 3.4 nm
  4. 656 nm
AIPMT 2000
8

Isoelectronic species are

  1. CO, CN-, NO+, C22-
  2. CO-, CN, NO, C2-
  3. CO+, CN+, NO-, C2
  4. CO, CN, NO, C2
AIPMT 2000

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