The value of Planck's constant is 6.63 10-34 J s. The velocity of light is 3.0 108 m s-1. Which value is closest to the wavelength in nanometers of a quantum of light with frequency of 8 1015 s-1 ?
- 2 10-25
- 5 10-18
- 4 101
- 3 107
Answer
(3) 4 101
Solution
c =
⇒ = c = 3.0 108 m s-18 1015 s-1
⇒ = 3.75 10-8 m
⇒ = 37.5 nm 4 101 nm
(Planck's constant is not needed for the wavelength.)
Answer: (3)