Let a=2 i+3 j+3 k and b=6 i+3 j+3 k. Then the square of the area of the triangle with adjacent sides determined by the vectors (2 a+3 b ) and ( a- b ) is :
- 450
- 900
- 1800
- 2400
Answer
(3) 1800
Solution
(2 a+3 b ) ( a- b )=-2 a b+3 b a ( a a= b b= 0)
(2 a+3 b ) ( a- b )=-5 ( a b )
a b= vmatrix i & j & k\ 2 & 3 & 3\ 6 & 3 & 3 vmatrix=0 i+12 j-12 k
| a b |=12 2
Area of triangle = 12 5 12 2=30 2
(Area)2=900 2=1800
Answer: (3)