In the Lewis dot structure for NO2-, total number of valence electrons around nitrogen is .
Answer
8
Solution
NO2-: valence electrons = 5 + 2(6) + 1 = 18
[figure]
Around N: one N=O (4 e⁻) + one N–O (2 e⁻) + one lone pair (2 e⁻)
∴ Electrons around N = 4 + 2 + 2 = 8 (octet)
Answer: 8