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Solutions · Question 2

NEET (UG) 2026MCQMedium📈 Topic in 25% papers+4−1
1

Identify the correct statements : Choose the correct answer from the options given below :

  1. A, B and C only
  2. A, D and E only
  3. A and B only
  4. A and C only

Answer

(1) A, B and C only

Solution

A. Molality = 2.5/6075/1000 = 0.04170.075 = 0.556 m ⇒ correct

B. Molarity = 5/40450/1000 = 0.1250.450 = 0.278 M ⇒ correct

C. As per NCERT, solubility of gases in liquids decreases with rise in temperature; more O2 dissolves in cold water ⇒ correct

D. By Henry's law, solubility of a gas increases with increase in pressure ⇒ incorrect

E. xB = nBnA + nB ⇒ incorrect

∴ A, B and C only

Answer: (1)

NEET (UG) 2026

Keep practising — Solutions

2

Consider the following statements about the solutions formed by mixing two liquids.

  1. A and C only
  2. A and B only
  3. B and C only
  4. A only
RE-NEET (UG) 2026
3

In the light of the above statements, choose the most appropriate answer from the options given below.

  1. A is not correct but R is correct
  2. Both A and R are correct and R is the correct explanation of A
  3. Both A and R are correct but R is NOT the correct explanation of A
  4. A is correct but R is not correct
RE-NEET (UG) 2026
4

Which of the following aqueous solution will exhibit highest boiling point?

  1. 0.01 M Na2SO4
  2. 0.015 M C6H12O6
  3. 0.01 M Urea
  4. 0.01 M KNO3
NEET (UG) 2025
5

Match List-I with List-II Choose the correct answer from the options given below:

  1. A-III, B-I, C-IV, D-II
  2. A-III, B-II, C-I, D-IV
  3. A-II, B-IV, C-I, D-III
  4. A-II, B-I, C-IV, D-III
NEET (UG) 2025
6

5 moles of liquid X and 10 moles of liquid Y make a solution having a vapour pressure of 70 torr. The vapour pressures of pure X and Y are 63 torr and 78 torr respectively. Which of the following is true regarding the described solution?

  1. The solution is ideal.
  2. The solution has volume greater than the sum of individual volumes.
  3. The solution shows positive deviation.
  4. The solution shows negative deviation.
NEET (UG) 2025
7

The Henry's law constant (KH) values of three gases (A, B, C) in water are 145, 2 10-5 and 35 kbar respectively. The solubility of these gases in water follows the order:

  1. B > A > C
  2. B > C > A
  3. A > C > B
  4. A > B > C
NEET (UG) 2024
8

The plot of osmotic pressure ( ) vs concentration ( mol L-1) for a solution gives a straight line with slope 25.73 L bar mol-1. The temperature at which the osmotic pressure measurement is done is (Use R = 0.083 L bar mol-1 K-1)

  1. 37
  2. 310
  3. 25.73
  4. 12.05
NEET (UG) 2024
9

Arrange the following compounds in increasing order of their solubilities in chloroform: NaCl, CH3OH, cyclohexane, CH3CN

  1. NaCl < CH3CN < CH3OH < Cyclohexane
  2. CH3OH < CH3CN < NaCl < Cyclohexane
  3. NaCl < CH3OH < CH3CN < Cyclohexane
  4. Cyclohexane < CH3CN < CH3OH < NaCl
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10

Mass of glucose ( C6H12O6) required to be dissolved to prepare one litre of its solution which is isotonic with 15 g L-1 solution of urea (NH2CONH2) is (Given: Molar mass in g mol-1 C : 12, H : 1, O : 16, N : 14)

  1. 55 g
  2. 15 g
  3. 30 g
  4. 45 g
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11

KH value for some gases at the same temperature 'T' are given : [figure] where KH is Henry's Law constant in water. The order of their solubility in water is :

  1. HCHO < CH4 < CO2 < Ar
  2. Ar < CO2 < CH4 < HCHO
  3. Ar < CH4 < CO2 < HCHO
  4. HCHO < CO2 < CH4 < Ar
NEET (UG) 2022 (Phase 2)

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