The Henry's law constant (KH) values of three gases (A, B, C) in water are 145, 2 10-5 and 35 kbar respectively. The solubility of these gases in water follows the order:
- B > A > C
- B > C > A
- A > C > B
- A > B > C
Answer
(2) B > C > A
Solution
Henry's law: p = KH x
x = pKH, so at the same partial pressure, solubility 1KH.
KH: B (2 10-5) < C (35) < A (145)
Solubility: B > C > A
Answer: (2)