Solutions · Question 9

Arrange the following compounds in increasing order of their solubilities in chloroform: NaCl, CH3OH, cyclohexane, CH3CN

1. NaCl < CH3CN < CH3OH < Cyclohexane
2. CH3OH < CH3CN < NaCl < Cyclohexane
3. NaCl < CH3OH < CH3CN < Cyclohexane
4. Cyclohexane < CH3CN < CH3OH < NaCl

Mass of glucose ( C6H12O6) required to be dissolved to prepare one litre of its solution which is isotonic with 15 g L-1 solution of urea (NH2CONH2) is (Given: Molar mass in g mol-1 C : 12, H : 1, O : 16, N : 14)

1. 55 g
2. 15 g
3. 30 g
4. 45 g

KH value for some gases at the same temperature 'T' are given : [figure] where KH is Henry's Law constant in water. The order of their solubility in water is :

1. HCHO < CH4 < CO2 < Ar
2. Ar < CO2 < CH4 < HCHO
3. Ar < CH4 < CO2 < HCHO
4. HCHO < CO2 < CH4 < Ar

The following solutions were prepared by dissolving 10 g of glucose ( C6H12O6) in 250 ml of water (P1), 10 g of urea (CH4N2O) in 250 ml of water (P2) and 10 g of sucrose ( C12H22O11) in 250 ml of water (P3). The right option for the decreasing order of osmotic pressure of these solutions is :

1. P3 > P1 > P2
2. P2 > P1 > P3
3. P1 > P2 > P3
4. P2 > P3 > P1

The correct option for the value of vapour pressure of a solution at 45 C with benzene to octane in molar ratio 3 : 2 is : [At 45 C vapour pressure of benzene is 280 mm Hg and that of octane is 420 mm Hg. Assume ideal solution]

1. 350 mm of Hg
2. 160 mm of Hg
3. 168 mm of Hg
4. 336 mm of Hg

The freezing point depression constant (Kf) of benzene is 5.12 K kg mol-1. The freezing point depression for the solution of molality 0.078 m containing a non-electrolyte solute in benzene is rounded off upto two decimal places :

1. 0.80 K
2. 0.40 K
3. 0.60 K
4. 0.20 K

The mixture which shows positive deviation from Raoult's law is :

1. Benzene + Toluene
2. Acetone + Chloroform
3. Chloroethane + Bromoethane
4. Ethanol + Acetone

For an ideal solution, the correct option is :

1. mix H = 0 at constant T and P
2. mix G = 0 at constant T and P
3. mix S = 0 at constant T and P
4. mix V 0 at constant T and P

The mixture that forms maximum boiling azeotrope is :

1. Ethanol + Water
2. Acetone + Carbon disulphide
3. Heptane + Octane
4. Water + Nitric acid

If molality of the dilute solution is doubled, the value of molal depression constant (Kf) will be

1. halved
2. tripled
3. unchanged
4. doubled.