Pair of species among the following having same bond order as well as paramagnetic character will be-
- O2-, N2+
- O2+, N22-
- O2-, N2-
- O2+, N2-
Answer
(4) O2+, N2-
Solution
Bond order = 12(Nb - Na) (MO theory).
O2+ (15 e-): 10 - 52 = 2.5; one unpaired e- in * paramagnetic
O2- (17 e-): 10 - 72 = 1.5; paramagnetic
N2+ (13 e-): 9 - 42 = 2.5; paramagnetic
N2- (15 e-): 10 - 52 = 2.5; paramagnetic
N22- (16 e-): 10 - 62 = 2; paramagnetic
(1) 1.5, 2.5; (2) 2.5, 2; (3) 1.5, 2.5; (4) 2.5, 2.5
O2+ and N2- have the same bond order (2.5) and both are paramagnetic.
Answer: (4)