A square loop PQRS having 10 turns, area 3.6 10-3 m2 and resistance 100 is slowly and uniformly being pulled out of a uniform magnetic field of magnitude B = 0.5 T as shown. Work done in pulling the loop out of the field in 1.0 s is 10-6 J. [figure]
Answer
3
Solution
Side l = 3.6 10-3 = 6 10-2 m; the loop leaves the field in 1 s, so v = 6 10-2 m/s
Only the side still inside the field cuts flux, so = NBlv and i = NBlvR
The magnetic force on this side opposes the pull: F = N(ilB) = N2B2l2vR
F = 100 0.25 3.6 10-3 6 10-2100 = 5.4 10-5 N
Since the pull is slow and uniform, the applied force equals F over the distance l:
W = F l = 5.4 10-5 6 10-2 = 3.24 10-6 J 3 10-6 J
Answer: 3