A square loop of side 15 cm is being moved towards right at a constant speed of 2 cm/s as shown in figure. The front edge enters the 50 cm wide magnetic field at t = 0. The value of induced emf in the loop at t = 10 s will be : [figure]
- zero
- 4.5 mV
- 0.3 mV
- 3 mV
Answer
(1) zero
Solution
In 10 s the loop moves 2 10 = 20 cm, so its front edge is 20 cm and its back edge 5 cm inside the 50 cm wide field.
The whole loop is now inside the uniform field, so the flux = BA stays constant.
e = - d dt = 0
Answer: (1)