A galvanometer (G) of 2 resistance is connected in the given circuit. The ratio of charge stored in C1 and C2 is : [figure]
- 1
- 23
- 32
- 12
Answer
(4) 12
Solution
in steady state no current flows through a capacitor, the current path is 4 Ω → G (2 Ω) → 6 Ω:
[figure]
I= 64+2+6=0.5 A
VC1=I(4+2)=3 V, VC2=I(2+6)=4 V
q1=4 3 V=12 , q2=6 4 V=24
q1q2= 1224= 12
Answer: (4)