When Hvap = 30 kJ/mol and Svap = 75 J mol-1 K-1, then the temperature of vapour, at one atmosphere is K.
Answer
400
Solution
At the boiling point (1 atm) liquid and vapour are in equilibrium, so G = H - T S = 0:
T = Hvap Svap = 30 103 J mol-175 J mol-1 K-1 = 400 K
Answer: 400