A student has planned to prepare acetanilide from aniline using acetic anhydride. The student has started from 9.3 g of aniline. However, the student has managed to obtain 11 g of dry acetanilide. The % yield of this reaction is :-
- 59.5\%
- 72.5\%
- 97.5\%
- 81.5\%
Answer
(4) 81.5\%
Solution
C6H5NH2 + (CH3CO)2O C6H5NHCOCH3 + CH3COOH
Aniline: 9.393 = 0.1 mol acetanilide expected = 0.1 mol
Theoretical mass = 0.1 135 = 13.5 g
% yield = 1113.5 100 = 81.5\%
Answer: (4)