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Some Basic Concepts of Chemistry · Question 28

JEE Main 2025 (Online) 2nd April Morning ShiftMCQEasy📈 Topic in 42% papers+4−1
1

CaCO3(s)+2HCl(aq) CaCl2(aq)+CO2(g)+H2O(l) Consider the above reaction, what mass of CaCl2 will be formed if 250 mL of 0.76 M HCl reacts with 1000 g of CaCO3 ? (Given : Molar mass of Ca, C, O, H and Cl are 40, 12, 16, 1 and 35.5 g mol-1, respectively)

  1. 3.908 g
  2. 2.636 g
  3. 10.545 g
  4. 5.272 g

Answer

(3) 10.545 g

Solution

Moles of HCl = 0.76 0.250 = 0.19 mol

Moles of CaCO3 = 1000100 = 10 mol

10 mol CaCO3 needs 20 mol HCl, but only 0.19 mol is present HCl is the limiting reagent.

2 mol HCl 1 mol CaCl2

Moles of CaCl2 = 0.192 = 0.095 mol

Molar mass of CaCl2 = 40 + 2 35.5 = 111 g mol-1

Mass of CaCl2 = 0.095 111 = 10.545 g

Answer: (3)

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2

On complete combustion 1.0 g of an organic compound (X) gave 1.46 g of CO2 and 0.567 g of H2O. The empirical formula mass of compound (X) is g. (Given molar mass in g mol-1 C : 12, H : 1, O : 16)

  1. 60
  2. 45
  3. 30
  4. 15
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3

0.1 mol of the following given antiviral compound (P) will weigh 10-1 g (nearest integer). [figure] (Given : molar mass in g mol-1 H : 1, C : 12, N : 14, O : 16, F : 19, I : 127)

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4

'x' g of NaCl is added to water in a beaker with a lid. The temperature of the system is raised from 1 C to 25 C. Which out of the following plots, is best suited for the change in the molarity (M) of the solution with respect to temperature? [Consider the solubility of NaCl remains unchanged over the temperature range]

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
JEE Main 2025 (Online) 2nd April Evening Shift
5

Choose the correct statements. Choose the correct answer from the options given below :

  1. (B), (C) and (D) Only
  2. (A), (B) and (C) Only
  3. (C), (D) and (E) Only
  4. (A), (D) and (E) Only
JEE Main 2025 (Online) 29th January Morning Shift
6

The molarity of a 70\% (mass/mass) aqueous solution of a monobasic acid (X) is 10-1 M (Nearest integer) [Given: Density of aqueous solution of (X) is 1.25 g mL-1 Molar mass of the acid is 70 g mol-1]

JEE Main 2025 (Online) 28th January Morning Shift
7

Quantitative analysis of an organic compound (X) shows following % composition. C : 14.5\% Cl : 64.46\% H : 1.8\% Empirical formula mass of the compound (X) is 10-1 (Given molar mass in g mol-1 of C : 12, H : 1, O : 16, Cl : 35.5)

JEE Main 2025 (Online) 28th January Morning Shift
8

Concentrated nitric acid is labelled as 75% by mass. The volume in mL of the solution which contains 30 g of nitric acid is . Given : Density of nitric acid solution is 1.25 g/mL.

  1. 32
  2. 40
  3. 55
  4. 45
JEE Main 2025 (Online) 28th January Evening Shift

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