A bag contains (N+1) coins - N fair coins, and one coin with 'Head' on both sides. A coin is selected at random and tossed. If the probability of getting 'Head' is 916, then N is equal to :
- 5
- 7
- 8
- 9
Answer
(2) 7
Solution
E1 : a fair coin is chosen, P (E1 )= NN+1, P (H|E1 )= 12
E2 : the two-headed coin is chosen, P (E2 )= 1N+1, P (H|E2 )=1
Total probability : P(H)= NN+1 12+ 1N+1 1= N+22(N+1)
N+22(N+1)= 916
16N+32=18N+18
2N=14 N=7
Answer: (2)