A transparent block A having refractive index = 1.25 is surrounded by another medium of refractive index = 1.0 as shown in the figure. A light ray is incident on the flat face of the block with incident angle as shown in the figure. What is the maximum value of for which light suffers total internal reflection at the top surface of the block? [figure]
- -1(4/3)
- -1(3/4)
- -1(3/4)
- -1(3/4)
Answer
(2) -1(3/4)
Solution
Critical angle at the top surface: C = 1 2 = 11.25 = 45 C = 35
Let r be the angle of refraction at the vertical face. The two normals are perpendicular, so the angle of incidence at the top surface is 90 - r.
For TIR: 90 - r C r 90 - C
is maximum when r = 90 - C r = C = 35
Snell's law at the vertical face: 1 = 2 r
1.0 = 1.25 35 = 34
= -1(3/4)
Answer: (2)