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Hydrocarbons · Question 47

AIPMT 2007MCQEasy📈 Topic in 62% papers+4−1
1

Which of the compound with molecular formula C5H10 yields acetone on ozonolysis?

  1. 3-Methyl-1-butene
  2. Cyclopentane
  3. 2-Methyl-1-butene
  4. 2-Methyl-2-butene

Answer

(4) 2-Methyl-2-butene

Solution

On ozonolysis each doubly bonded carbon becomes a C=O group. To get acetone, one carbon of the C=C bond must carry two CH3 groups.

2-Methyl-2-butene: CH3- CH3 |C=CH-CH3

⇒ CH3- CH3 |C=CH-CH3 [Zn/H2O]O3

CH3- O \|C-CH3 + CH3CHO

3-Methyl-1-butene gives (CH3)2CHCHO + HCHO; 2-methyl-1-butene gives butan-2-one + HCHO; cyclopentane has no C=C bond.

∴ 2-Methyl-2-butene yields acetone.

Answer: (4)

AIPMT 2007

Keep practising — Hydrocarbons

2

The correct order regarding the electronegativity of hybrid orbitals of carbon is

  1. sp < sp2 < sp3
  2. sp > sp2 < sp3
  3. sp > sp2 > sp3
  4. sp < sp2 > sp3
AIPMT 2006
3

Which one of the following alkenes will react faster with H2 under catalytic hydrogenation conditions ?

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
AIPMT 2005
4

Products of the following reaction : CH3C CCH2CH3 [(ii) hydrolysis](i) O3 are

  1. CH3COOH + CO2
  2. CH3COOH + HOOC.CH2CH3
  3. CH3CHO + CH3CH2CHO
  4. CH3COOH + CH3COCH3
AIPMT 2005
5

Using anhydrous AlCl3 as catalyst, which one of the following reactions produces ethylbenzene (PhEt)?

  1. H3C-CH2OH + C6H6
  2. CH3-CH=CH2 + C6H6
  3. H2C=CH2 + C6H6
  4. H3C-CH3 + C6H6
AIPMT 2004
6

Reaction of HBr with propene in the presence of peroxide gives

  1. isopropyl bromide
  2. 3-bromopropane
  3. allyl bromide
  4. n-propyl bromide
AIPMT 2004
7

The compound CH3- CH3 |C=CH-CH3 on reaction with NaIO4 in the presence of KMnO4 gives

  1. CH3COCH3
  2. CH3COCH3 + CH3COOH
  3. CH3COCH3 + CH3CHO
  4. CH3CHO + CO2
AIPMT 2003
8

The correct order of reactivity towards the electrophilic substitution of the compounds aniline (I), benzene (II) and nitrobenzene (III) is

  1. III > II > I
  2. II > III > I
  3. I < II > III
  4. I > II > III
AIPMT 2003
9

When CH3CH2CHCl2 is treated with NaNH2, the product formed is

  1. CH3-CH=CH2
  2. CH3-C CH
  3. [figure]
  4. [figure]
AIPMT 2002
10

Which alkene on ozonolysis gives CH3CH2CHO and CH3COCH3?

  1. [figure]
  2. CH3CH2CH=CHCH2CH3
  3. CH3CH2CH=CHCH3
  4. [figure]
AIPMT 2001
11

Increasing order of electrophilic substitution for following compounds [figure]

  1. IV < I < II < III
  2. III < II < I < IV
  3. I < IV < III < II
  4. II < III < I < IV
AIPMT 2000

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