In a tournament, a team plays 10 matches with probabilities of winning and losing each match as 13 and 23 respectively. Let x be the number of matches that the team wins, and y be the number of matches that team loses. If the probability P(|x - y| 2) is p, then 39 p equals .
Answer
8288
Solution
x + y = 10 |x - y| = |2x - 10| 2 x = 4, 5, 6
Binomial: n = 10, P(win) = 13, P(loss) = 23
p = 10C4 26 + 10C5 25 + 10C6 24310
= 210 64 + 252 32 + 210 16310 = 24864310
39 p = 248643 = 8288
Answer: 8288