If the mean of the following probability distribution of a random variable X : [figure] is 469, then the variance of the distribution is
- 58181
- 56681
- 15127
- 17327
Answer
(2) 56681
Solution
P = 1: 4a + 6b = 1 …(i)
Mean: 4(2a) + 4(a + b) + 6(2b) + 8(3b) = 8a + 40b = 469 …(ii)
(ii) − 2 × (i): 28b = 469 - 2 = 289 ⇒ b = 19, a = 112
E(X2) = 4(2a) + 16(a + b) + 36(2b) + 64(3b)
= 24a + 280b = 2 + 2809 = 2989
Var(X) = E(X2) - [E(X)]2
= 2989 - 211681 = 56681
Answer: (2)