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p-Block Elements (Group 15–18) · Question 2

JEE Advanced 2026 Paper 1Multiple CorrectMedium📈 Topic in 17% papers+4−1
1

Reaction of PtF6 with oxygen (O2) gas results in the formation of an ionic compound, X+Y-. Correct statement(s) is(are)

  1. The bond order of X+ is 1.5.
  2. Valence d-orbitals of the metal ion in X+Y- has 5 electrons.
  3. PtF6 acts as an oxidant in this reaction.
  4. PtF6 acts as a fluorinating agent in this reaction.

Answer

(2) Valence d-orbitals of the metal ion in X+Y- has 5 electrons., (3) PtF6 acts as an oxidant in this reaction.

Solution

O2 + PtF6 O2+[PtF6]-, so X⁺ = O2+ and Y⁻ = [PtF6]-.

(A) O2+ has 15 electrons, so its bond order = 10-52 = 2.5, not 1.5. Wrong.

(B) In [PtF6]-, Pt is +5. Pt is 5d96s1, so Pt5+ is 5d5. Correct.

(C) PtF6 takes an electron from O2 and is reduced, so it is the oxidant. Correct.

(D) No F atom is transferred to oxygen, so it is not a fluorinating agent here. Wrong.

Answer: (B), (C)

JEE Advanced 2026 Paper 1

Keep practising — p-Block Elements (Group 15–18)

2

Correct statement(s) about the compounds P, Q and R is(are) Xe(g)+F2(g) (1:5 ratio) 873 K, 7 barP P+O2F2 143 KQ+O2 Q+H2O complete hydrolysisR+HF

  1. P has two lone pairs of electrons on the central atom.
  2. Q has a perfect octahedral geometry.
  3. Q can act as a fluorinating agent.
  4. The molecular structure of R is trigonal pyramidal.
JEE Advanced 2026 Paper 2
3

The heating of NH4NO2 at 60−70 °C and NH4NO3 at 200−250 °C is associated with the formation of nitrogen containing compounds X and Y, respectively. X and Y, respectively, are

  1. N2 and N2O
  2. NH3 and NO2
  3. NO and N2O
  4. N2 and NH3
JEE Advanced 2025 Paper 1
4

The complete hydrolysis of ICl, ClF3 and BrF5, respectively, gives

  1. IO-, ClO2- and BrO3-
  2. IO3-, ClO2- and BrO3-
  3. IO-, ClO- and BrO2-
  4. IO3-, ClO4- and BrO2-
JEE Advanced 2025 Paper 2
5

The compound(s) with P–H bond(s) is(are)

  1. H3PO4
  2. H3PO3
  3. H4P2O7
  4. H3PO2
JEE Advanced 2025 Paper 2
6

At room temperature, disproportionation of an aqueous solution of in situ generated nitrous acid (HNO2) gives the species

  1. H3O+, NO3- and NO
  2. H3O+, NO3- and NO2
  3. H3O+, NO- and NO2
  4. H3O+, NO3- and N2O
JEE Advanced 2024 Paper 1
7

Based on VSEPR model, match the xenon compounds given in List-I with the corresponding geometries and the number of lone pairs on xenon given in List-II and choose the correct option.

  1. P-5, Q-2, R-3, S-1
  2. P-5, Q-3, R-2, S-4
  3. P-4, Q-3, R-2, S-1
  4. P-4, Q-2, R-5, S-3
JEE Advanced 2024 Paper 1
8

The species formed on fluorination of phosphorus pentachloride in a polar organic solvent are

  1. [PF4]+[PF6]- and [PCl4]+[PF6]-
  2. [PCl4]+[PCl4F2]- and [PCl4]+[PF6]-
  3. PF3 and PCl3
  4. PF5 and PCl3
JEE Advanced 2024 Paper 2
9

The compound(s) having peroxide linkage is(are)

  1. H2S2O7
  2. H2S2O8
  3. H2S2O5
  4. H2SO5
JEE Advanced 2024 Paper 2

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