Reaction of PtF6 with oxygen (O2) gas results in the formation of an ionic compound, X+Y-. Correct statement(s) is(are)
- The bond order of X+ is 1.5.
- Valence d-orbitals of the metal ion in X+Y- has 5 electrons.
- PtF6 acts as an oxidant in this reaction.
- PtF6 acts as a fluorinating agent in this reaction.
Answer
(2) Valence d-orbitals of the metal ion in X+Y- has 5 electrons., (3) PtF6 acts as an oxidant in this reaction.
Solution
O2 + PtF6 O2+[PtF6]-, so X⁺ = O2+ and Y⁻ = [PtF6]-.
(A) O2+ has 15 electrons, so its bond order = 10-52 = 2.5, not 1.5. Wrong.
(B) In [PtF6]-, Pt is +5. Pt is 5d96s1, so Pt5+ is 5d5. Correct.
(C) PtF6 takes an electron from O2 and is reduced, so it is the oxidant. Correct.
(D) No F atom is transferred to oxygen, so it is not a fluorinating agent here. Wrong.
Answer: (B), (C)