p-Block Elements (Group 15–18) · Question 1

Reaction of PtF6 with oxygen (O2) gas results in the formation of an ionic compound, X+Y-. Correct statement(s) is(are)

1. The bond order of X+ is 1.5.
2. Valence d-orbitals of the metal ion in X+Y- has 5 electrons.
3. PtF6 acts as an oxidant in this reaction.
4. PtF6 acts as a fluorinating agent in this reaction.

Correct statement(s) about the compounds P, Q and R is(are) Xe(g)+F2(g) (1:5 ratio) 873 K, 7 barP P+O2F2 143 KQ+O2 Q+H2O complete hydrolysisR+HF

1. P has two lone pairs of electrons on the central atom.
2. Q has a perfect octahedral geometry.
3. Q can act as a fluorinating agent.
4. The molecular structure of R is trigonal pyramidal.

The heating of NH4NO2 at 60−70 °C and NH4NO3 at 200−250 °C is associated with the formation of nitrogen containing compounds X and Y, respectively. X and Y, respectively, are

1. N2 and N2O
2. NH3 and NO2
3. NO and N2O
4. N2 and NH3

The complete hydrolysis of ICl, ClF3 and BrF5, respectively, gives

1. IO-, ClO2- and BrO3-
2. IO3-, ClO2- and BrO3-
3. IO-, ClO- and BrO2-
4. IO3-, ClO4- and BrO2-

The compound(s) with P–H bond(s) is(are)

1. H3PO4
2. H3PO3
3. H4P2O7
4. H3PO2

At room temperature, disproportionation of an aqueous solution of in situ generated nitrous acid (HNO2) gives the species

1. H3O+, NO3- and NO
2. H3O+, NO3- and NO2
3. H3O+, NO- and NO2
4. H3O+, NO3- and N2O

Based on VSEPR model, match the xenon compounds given in List-I with the corresponding geometries and the number of lone pairs on xenon given in List-II and choose the correct option.

1. P-5, Q-2, R-3, S-1
2. P-5, Q-3, R-2, S-4
3. P-4, Q-3, R-2, S-1
4. P-4, Q-2, R-5, S-3

The species formed on fluorination of phosphorus pentachloride in a polar organic solvent are

1. [PF4]+[PF6]- and [PCl4]+[PF6]-
2. [PCl4]+[PCl4F2]- and [PCl4]+[PF6]-
3. PF3 and PCl3
4. PF5 and PCl3

The compound(s) having peroxide linkage is(are)

1. H2S2O7
2. H2S2O8
3. H2S2O5
4. H2SO5