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Coordination Compounds · Question 51

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1

A transition metal (M) among Mn, Cr, Co and Fe has the highest standard electrode potential (M3+/M2+). It forms a metal complex of the type [M(CN)6]4-. The number of electrons present in the eg orbital of the complex is .

Answer

1

Solution

E M3+/M2+: Cr = -0.41 V, Mn = +1.57 V, Fe = +0.77 V, Co = +1.97 V

M = Co (highest value)

In [Co(CN)6]4-: x + 6(-1) = -4 x = +2

Co2+: 3d7

CN- is a strong field ligand low spin octahedral complex ( o > P)

Configuration: t2g6 eg1

Number of electrons in eg orbitals = 1

Answer: 1

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Keep practising — Coordination Compounds

2

The type of hybridization and the magnetic property of [MnCl6]3- are,

  1. sp3d2, paramagnetic with four unpaired electrons.
  2. d2sp3, paramagnetic with four unpaired electrons.
  3. sp3d2, paramagnetic with two unpaired electrons.
  4. d2sp3, paramagnetic with two unpaired electrons.
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3

The d-orbital electronic configuration of the complex among [Co(en)3]3+, [CoF6]3-, [Mn(H2O)6]2+ and [Zn(H2O)6]2+ that has the highest CFSE is:

  1. t2g6eg0
  2. t2g3eg2
  3. t2g4eg2
  4. t2g6eg4
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4

The correct increasing order of stability of the complexes based on 0 value is : I. [Mn(CN)6]3- II. [Co(CN)6]4- III. [Fe(CN)6]4- IV. [Fe(CN)6]3-

  1. I < II < IV < III
  2. IV < III < II < I
  3. III < II < IV < I
  4. II < III < I < IV
JEE Main 2025 (Online) 29th January Morning Shift
5

Match List - I with List - II. Choose the correct answer from the options given below :

  1. (A)-(III), (B)-(I), (C)-(I), (D)-(IV)
  2. (A)-(III), (B)-(II), (C)-(III), (D)-(IV)
  3. (A)-(IV), (B)-(II), (C)-(I), (D)-(III)
  4. (A)-(IV), (B)-(I), (C)-(II), (D)-(III)
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6

Match List - I with List - II. Choose the correct answer from the options given below:

  1. (A)-(I), (B)-(II), (C)-(III), (D)-(IV)
  2. (A)-(III), (B)-(IV), (C)-(I), (D)-(II)
  3. (A)-(I), (B)-(IV), (C)-(III), (D)-(II)
  4. (A)-(III), (B)-(II), (C)-(I), (D)-(IV)
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