Let 3, 7, 11, 15, , 403 and 2, 5, 8, 11, , 404 be two arithmetic progressions. Then the sum, of the common terms in them, is equal to .
Answer
6699
Solution
First common term =11; common difference =LCM(4, 3)=12
Common terms: 11, 23, 35, up to 403
11+(n-1)12 403 n-1 32.6 n=33, last term =11+32 12=395
∴ Sum = 332(11+395)=33 203=6699
Answer: 6699