The solubility product of AgI at 25 C is 1.0 10-16 mol2 L-2. The solubility of AgI in 10-4 N solution of KI at 25 C is approximately (in mol L-1)
- 1.0 10-16
- 1.0 10-12
- 1.0 10-10
- 1.0 10-8
Answer
(2) 1.0 10-12
Solution
For KI, normality = molarity ⇒ [I-] = 10-4 mol L-1 (common ion).
Let the solubility of AgI be s: [Ag+] = s, [I-] = s + 10-4 10-4 (s is very small)
Ksp = [Ag+][I-]
⇒ 1.0 10-16 = s 10-4
⇒ s = 1.0 10-12 mol L-1
Answer: (2)