A cricket ball is thrown by a player at a speed of 20 m/s in a direction 30 above the horizontal. The maximum height attained by the ball during its motion is (g = 10 m/s2)
- 25 m
- 5 m
- 10 m
- 20 m
Answer
(2) 5 m
Solution
Maximum height of a projectile: H = u2 2 2g
H = (20)2 2 30 2 10
= 400 1420
= 5 m
Answer: (2)