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Application of Integrals · Question 22

JEE Main 2025 (Online) 7th April Evening ShiftMCQMedium📈 Topic in 74% papers+4−1
1

If the area of the region \(x, y) : 1 + x2 y \x + 7, 11 - 3x\\ is A, then 3A is equal to :

  1. 50
  2. 46
  3. 49
  4. 47

Answer

(1) 50

Solution

Lines y = x + 7 and y = 11 - 3x meet at (1, 8); for x 1 the smaller one is x + 7, for x 1 it is 11 - 3x.

1 + x2 = x + 7 x2 - x - 6 = 0 x = -2 (also 3, outside the region)

1 + x2 = 11 - 3x x2 + 3x - 10 = 0 x = 2 (also −5, outside the region)

[figure]

A = -21 (x + 7 - 1 - x2) dx + 12 (11 - 3x - 1 - x2) dx

= [6x + x22 - x33 ]-21 + [10x - 3x22 - x33 ]12

= ( 376 + 223 ) + ( 343 - 496 )

= 272 + 196 = 503

3A = 50

Answer: (1)

JEE Main 2025 (Online) 7th April Evening Shift

Keep practising — Application of Integrals

2

If the area of the region \(x, y) : |x - 5| y 4 x\ is A, then 3A is equal to .

JEE Main 2025 (Online) 4th April Morning Shift
3

A line passing through the point A(-2, 0) touches the parabola P: y2 = x - 2 at the point B in the first quadrant. The area of the region bounded by the line AB, parabola P and the x-axis, is :

  1. 3
  2. 73
  3. 83
  4. 2
JEE Main 2025 (Online) 4th April Evening Shift
4

The area of the region bounded by the curve y = \|x|, x|x-2|\, the x-axis and the lines x = -2 and x = 4 is equal to

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5

The area of the region \(x, y) : |x - y| y 4 x\ is

  1. 5123
  2. 20483
  3. 512
  4. 10243
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6

If the area of the region \(x, y) : |4 - x2 | y x2, y 4, x 0 \ is ( 80 2 - ), , N, then + is equal to .

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7

Let the area of the region \(x, y) : 2y x2 + 3, y + |x| 3, y |x - 1|\ be A. Then 6A is equal to :

  1. 14
  2. 18
  3. 16
  4. 12
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8

The area (in sq. units) of the region \(x, y) : 0 y 2|x| + 1, 0 y x2 + 1, |x| 3\ is

  1. 323
  2. 643
  3. 173
  4. 803
JEE Main 2025 (Online) 28th January Morning Shift
9

The area of the region bounded by the curves x(1 + y2) = 1 and y2 = 2x is:

  1. 4 - 13
  2. 2 - 13
  3. 2 ( 2 - 13 )
  4. 12 ( 2 - 13 )
JEE Main 2025 (Online) 28th January Evening Shift

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