Two ideal diodes are connected to a battery as shown in the circuit. The current supplied by the battery is [figure]
- 0.75 A
- zero
- 0.25 A
- 0.5 A
Answer
(4) 0.5 A
Solution
The longer plate (positive terminal) of the battery is on the left, so conventional current leaves the battery towards the left and reaches both branches from the left end.
D1 points from left to right forward biased (ideal: zero resistance).
D2 points from right to left reverse biased (ideal: open circuit), so no current flows through the 20 branch.
I = VR = 510 = 0.5 A
Answer: (4)