Given below are two statements : In the light of the above statements, choose the correct answer from the options given below
- Both Statement I and Statement II are false
- Statement I is true but Statement II is false
- Statement I is false but Statement II is true
- Both Statement I and Statement II are true
Answer
(1) Both Statement I and Statement II are false
Solution
Statement I:
BF4-: sp3, tetrahedral all four B–F bonds equal
SiF4: sp3, tetrahedral all four Si–F bonds equal
XeF4: sp3d2, square planar (2 lone pairs axial) all four Xe–F bonds equal
SF4: sp3d, see-saw (lone pair equatorial) 2 axial S–F bonds are longer than 2 equatorial S–F bonds
only one species (SF4) has unequal E–F bond lengths Statement I is false.
Statement II: bond order = 12(Nb - Na)
O2+ (15 e⁻): 10 - 52 = 2.5
O2- (17 e⁻): 10 - 72 = 1.5
O22- (18 e⁻): 10 - 82 = 1
F2 (18 e⁻): 10 - 82 = 1
O2+ (not O2-) has the highest bond order Statement II is false.
Answer: (1)