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Chemical Bonding and Molecular Structure · Question 10

JEE Main 2026 (Online) 2nd April Evening ShiftMCQMedium📈 Topic in 32% papers+4−1
1

SF4 is isostructural with : Choose the correct answer from the options given below :

  1. C Only
  2. C and E Only
  3. A and D Only
  4. B and E Only

Answer

(2) C and E Only

Solution

SF4: S has 6 valence electrons ⇒ 4 bond pairs + 1 lone pair (sp³d) ⇒ see-saw.

A. BrF4 : 7 + 1 = 8 e ⇒ 4 bp + 2 lp ⇒ square planar

B. CH4: 4 bp ⇒ tetrahedral

C. IF4 : 7 − 1 = 6 e ⇒ 4 bp + 1 lp ⇒ see-saw ✓

D. XeF4: 4 bp + 2 lp ⇒ square planar

E. XeO2F2: 4 σ bonds + 1 lp (steric number 5) ⇒ see-saw ✓

∴ C and E only.

Answer: (2)

JEE Main 2026 (Online) 2nd April Evening Shift

Keep practising — Chemical Bonding and Molecular Structure

2

Given below are two statements : In the light of the above statements, choose the correct answer from the options given below

  1. Both Statement I and Statement II are false
  2. Statement I is true but Statement II is false
  3. Statement I is false but Statement II is true
  4. Both Statement I and Statement II are true
JEE Main 2026 (Online) 28th January Morning Shift
3

Match List-I with List-II according to shape. Choose the correct answer from the options given below :

  1. A-II, B-III, C-I, D-IV
  2. A-III, B-II, C-IV, D-I
  3. A-II, B-III, C-IV, D-I
  4. A-II, B-I, C-III, D-IV
JEE Main 2026 (Online) 28th January Evening Shift
4

Given below are statements about some molecules/ions. Identify the CORRECT statements. Choose the correct answer from the options given below:

  1. B & C Only
  2. B, C & D Only
  3. A, C & D Only
  4. A, B, C, D & E
JEE Main 2026 (Online) 24th January Morning Shift
5

Among the following, the CORRECT combinations are Choose the correct answer from the options given below:

  1. B, C and D Only
  2. A, B, C and D
  3. A, B and C Only
  4. A and B Only
JEE Main 2026 (Online) 24th January Morning Shift
6

Pair of species among the following having same bond order as well as paramagnetic character will be-

  1. O2-, N2+
  2. O2+, N22-
  3. O2-, N2-
  4. O2+, N2-
JEE Main 2026 (Online) 24th January Evening Shift
7

Identify the molecule (X) with maximum number of lone pairs of electrons (obtained using Lewis dot structure) among HNO3, H2SO4, NF3 and O3. Choose the correct bond angle made by the central atom of the molecule (X).

  1. 107
  2. 102
  3. 120
  4. 116
JEE Main 2026 (Online) 23rd January Morning Shift
8

Which statements are NOT TRUE about XeO2F2? Choose the correct answer from the options given below :

  1. B, D and E Only
  2. B and D Only
  3. B, C and E Only
  4. A and D Only
JEE Main 2026 (Online) 23rd January Evening Shift
9

Two p-block elements X and Y form fluorides of the type EF3. The fluoride compound XF3 is a Lewis acid and YF3 is a Lewis base. The hybridizations of the central atoms of XF3 and YF3 respectively are

  1. sp2 and sp3
  2. Both sp3
  3. Both sp2
  4. sp3 and sp2
JEE Main 2026 (Online) 22nd January Morning Shift
10

The formal charges on the atoms marked as (1) to (4) in the Lewis representation of HNO3 molecule respectively are [figure]

  1. 0, 0, -1, +1
  2. 0, -1, 0, +1
  3. 0, +1, 0, -1
  4. +1, 0, 0, -1
JEE Main 2026 (Online) 22nd January Morning Shift
11

Among H2S, H2O, NF3, NH3 and CHCl3, identify the molecule (X) with lowest dipole moment value. The number of lone pairs of electrons present on the central atom of the molecule (X) is :

  1. 3
  2. 2
  3. 0
  4. 1
JEE Main 2026 (Online) 22nd January Evening Shift

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