For the reaction, 2Cl(g) Cl2(g), the correct option is :
- r H > 0 and r S < 0
- r H < 0 and r S > 0
- r H < 0 and r S < 0
- r H > 0 and r S > 0
Answer
(3) r H < 0 and r S < 0
Solution
In 2Cl(g) Cl2(g) a Cl-Cl bond is formed.
Bond formation releases energy ⇒ r H < 0
Two moles of gaseous atoms give one mole of gaseous molecules ⇒ randomness decreases ⇒ r S < 0
Answer: (3)