Under isothermal condition, a gas at 300 K expands from 0.1 L to 0.25 L against a constant external pressure of 2 bar. The work done by the gas is [Given that 1 L bar = 100 J]
- 25 J
- 30 J
- −30 J
- 5 kJ
Answer
(3) −30 J
Solution
As per NCERT, for an irreversible expansion against a constant external pressure:
w = -pex V
= -2 bar (0.25 - 0.1) L
= -0.3 L bar
= -0.3 100 J = -30 J
The negative sign shows that work is done by the system (gas) on the surroundings.
Answer: (3)