The bond dissociation energies of X2, Y2 and XY are in the ratio of 1 : 0.5 : 1. H for the formation of XY is -200 kJ mol-1. The bond dissociation energy of X2 will be
- 800 kJ mol-1
- 200 kJ mol-1
- 400 kJ mol-1
- 100 kJ mol-1
Answer
(1) 800 kJ mol-1
Solution
Let the bond dissociation energies of X2, Y2 and XY be a, 0.5a and a.
Formation of XY: 12X2 + 12Y2 XY
H = 12a + 12(0.5a) - a
= -0.25a
⇒ -0.25a = -200
⇒ a = 800 kJ mol-1
Answer: (1)