Which of the following will give maximum number of isomers?
- [Co(NH3)4Cl2]
- [Ni(en)(NH3)4]2+
- [Ni(C2O4)(en)2]
- [Cr(SCN)2(NH3)4]+
Answer
(4) [Cr(SCN)2(NH3)4]+
Solution
(1) [Co(NH3)4Cl2], type [MA4B2]: cis and trans, i.e. 2 isomers.
(2) [Ni(en)(NH3)4]2+, type [M(AA)B4]: no isomer, i.e. 1 form only.
(3) [Ni(C2O4)(en)2], type [M(AA)2(BB)]: trans + cis (d and l), i.e. 3 isomers.
(4) [Cr(SCN)2(NH3)4]+: geometrical isomers cis and trans; besides, SCN is an ambidentate ligand (S- or N-bonded), so linkage isomers are also possible: both –SCN, one –SCN + one –NCS, both –NCS.
Total isomers = 2 3 = 6
[Cr(SCN)2(NH3)4]+ gives the maximum number of isomers.
Answer: (4)