CuSO4 when reacts with KCN forms CuCN, which is insoluble in water. It is soluble in excess of KCN, due to formation of the following complex
- K2[Cu(CN)4]
- K3[Cu(CN)4]
- CuCN2
- Cu[KCu(CN)4]
Answer
(2) K3[Cu(CN)4]
Solution
2CuSO4 + 4KCN 2Cu(CN)2 + 2K2SO4
2Cu(CN)2 2CuCN + (CN)2 (Cu(II) is reduced to Cu(I))
With excess KCN, CuCN dissolves forming a soluble Cu(I) complex:
CuCN + 3KCN K3[Cu(CN)4]
Check: Cu(+1) + 4(−1) = −3 [Cu(CN)4]3- needs 3 K+.
Answer: (2)