A moving coil of galvanometer when shunted with 2 resistance gives a full scale deflection for a current of 500 mA. When a resistance of 470 is connected in series it gives a full scale deflection for 10 V potential applied on it. The value of resistance of galvanometer coil is .
Answer
50
Solution
Let G = coil resistance, Ig = full-scale current.
With shunt S=2 (total current 0.5 A): IgG=(0.5-Ig)S
⇒ Ig(G+2)=0.5 2=1 ...(i)
With 470 in series (10 V): Ig(G+470)=10 ...(ii)
(ii) ÷ (i): G+470G+2=10
⇒ G+470=10G+20 ⇒ 9G=450
∴ G=50
Answer: 50