What fraction of Fe exists as Fe(III) in Fe0.96O ? (Consider Fe0.96O to be made up of Fe(II) and Fe(III) only)
- 120
- 112
- 0.08
- 116
Answer
(2) 112
Solution
Let Fe3+ = x, then Fe2+ = 0.96 – x (per formula unit).
Charge balance with one O2-:
3x + 2(0.96 - x) = 2
x + 1.92 = 2
x = 0.08
Fraction of Fe as Fe(III) = 0.080.96 = 112
Answer: (2)