The resistance per centimeter of a meter bridge wire is r, with X resistance in left gap. Balancing length from left end is at 40 cm with 25 resistance in right gap. Now the wire is replaced by another wire of 2r resistance per centimeter. The new balancing length for same settings will be at
- 10 cm
- 80 cm
- 40 cm
- 20 cm
Answer
(3) 40 cm
Solution
Balance: X25= r lr(100-l)= l100-l
r cancels, balance depends only on X and 25 , not on the wire's resistance per cm
With 2r: X25= 2r l'2r(100-l') l'=l=40 cm
Answer: (3)