Coordination Compounds

According to crystal field theory, the correct order of ligands with respect to their decreasing order of field strength is

1. Cl- > NH3 > H2O > CO
2. CO > NH3 > H2O > Cl-
3. CO > H2O > NH3 > Cl-
4. Cl- > H2O > NH3 > CO

Among the species given below, the spin-only magnetic moment is highest for (Given: Atomic number of Ti = 22, Mn = 25, Fe = 26 and Co = 27)

1. [Ti(H2O)6]3+
2. [Mn(CN)6]3-
3. [Fe(CN)6]3-
4. [Co(NH3)6]3+

Match List-I with List-II : Choose the correct answer from the options given below.

1. (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)
2. (a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)
3. (a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)
4. (a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)

Which of the following is the correct order of increasing field strength of ligands to form coordination compounds?

1. SCN- < F- < CN- < C2O42-
2. F- < SCN- < C2O42- < CN-
3. CN- < C2O42- < SCN- < F-
4. SCN- < F- < C2O42- < CN-

What is the correct electronic configuration of the central atom in K4[Fe(CN)6] based on crystal field theory?

1. t2g4 eg2
2. t2g6 eg0
3. e3 t23
4. e4 t22

Jahn-Teller effect is not observed in high spin complexes of

1. d7
2. d8
3. d4
4. d9

Which of these statements about [Co(CN)6]3- is true?

1. [Co(CN)6]3- has four unpaired electrons and will be in a high-spin configuration.
2. [Co(CN)6]3- has no unpaired electrons and will be in a high-spin configuration.
3. [Co(CN)6]3- has no unpaired electrons and will be in a low-spin configuration.
4. [Co(CN)6]3- has four unpaired electrons and will be in a low-spin configuration.

Among the following complexes the one which shows zero crystal field stabilization energy (CFSE) is

1. [Mn(H2O)6]3+
2. [Fe(H2O)6]3+
3. [Co(H2O)6]2+
4. [Co(H2O)6]3+

Crystal field splitting energy for high spin d4 octahedral complex is

1. -1.2 o
2. -0.6 o
3. -0.8 o
4. -1.6 o

Low spin complex of d6-cation in an octahedral field will have the following energy

1. -125 o + P
2. -125 o + 3P
3. -25 o + 2P
4. -25 o + P

Crystal field stabilization energy for high spin d4 octahedral complex is

1. -1.8 0
2. -1.6 0 + P
3. -1.2 0
4. -0.6 0

Which of the following complexes exhibits the highest paramagnetic behaviour? where gly = glycine, en = ethylenediamine and bpy = bipyridyl moieties. (At. nos. Ti = 22, V = 23, Fe = 26, Co = 27)

1. [Co(ox)2(OH)2]-
2. [Ti(NH3)6]3+
3. [V(gly)2(OH)2(NH3)2]+
4. [Fe(en)(bpy)(NH3)2]2+

In which of the following coordination entities the magnitude of o (CFSE in octahedral field) will be maximum? (At. No. Co = 27)

1. [Co(CN)6]3-
2. [Co(C2O4)3]3-
3. [Co(H2O)6]3+
4. [Co(NH3)6]3+

[Cr(H2O)6]Cl3 (At. no. of Cr = 24) has a magnetic moment of 3.83 B.M. The correct distribution of 3d electrons in the chromium of the complex is

1. 3d1xy, 3d1yz, 3d1z2
2. 3d1(x2-y2), 3d1z2, 3d1xz
3. 3d1xy, 3d1(x2-y2), 3d1yz
4. 3d1xy, 3d1yz, 3d1xz

CN- is a strong field ligand. This is due to the fact that

1. it carries negative charge
2. it is a pseudohalide
3. it can accept electrons from metal species
4. it forms high spin complexes with metal species.

Considering H2O as a weak field ligand, the number of unpaired electrons in [Mn(H2O)6]2+ will be (atomic number of Mn = 25)

1. three
2. five
3. two
4. four