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Application of Integrals · Question 21

JEE Main 2025 (Online) 7th April Morning ShiftMCQEasy📈 Topic in 74% papers+4−1
1

If the area of the region bounded by the curves y = 4 - x24 and y = x-42 is equal to , then 6 equals

  1. 210
  2. 250
  3. 240
  4. 220

Answer

(2) 250

Solution

Points of intersection: 4 - x24 = x-42

16 - x2 = 2x - 8 x2 + 2x - 24 = 0 x = -6, 4

Between them the parabola lies above the line.

= -64 [ (4 - x24 ) - x-42 ] dx = -64 (6 - x2 - x24 ) dx

= [6x - x24 - x312 ]-64

= (24 - 4 - 163 ) - (-36 - 9 + 18)

= 443 + 27 = 1253

6 = 250

Answer: (2)

JEE Main 2025 (Online) 7th April Morning Shift

Keep practising — Application of Integrals

2

If the area of the region \(x, y) : 1 + x2 y \x + 7, 11 - 3x\\ is A, then 3A is equal to :

  1. 50
  2. 46
  3. 49
  4. 47
JEE Main 2025 (Online) 7th April Evening Shift
3

If the area of the region \(x, y) : |x - 5| y 4 x\ is A, then 3A is equal to .

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4

A line passing through the point A(-2, 0) touches the parabola P: y2 = x - 2 at the point B in the first quadrant. The area of the region bounded by the line AB, parabola P and the x-axis, is :

  1. 3
  2. 73
  3. 83
  4. 2
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5

The area of the region bounded by the curve y = \|x|, x|x-2|\, the x-axis and the lines x = -2 and x = 4 is equal to

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6

The area of the region \(x, y) : |x - y| y 4 x\ is

  1. 5123
  2. 20483
  3. 512
  4. 10243
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7

If the area of the region \(x, y) : |4 - x2 | y x2, y 4, x 0 \ is ( 80 2 - ), , N, then + is equal to .

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8

Let the area of the region \(x, y) : 2y x2 + 3, y + |x| 3, y |x - 1|\ be A. Then 6A is equal to :

  1. 14
  2. 18
  3. 16
  4. 12
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9

The area (in sq. units) of the region \(x, y) : 0 y 2|x| + 1, 0 y x2 + 1, |x| 3\ is

  1. 323
  2. 643
  3. 173
  4. 803
JEE Main 2025 (Online) 28th January Morning Shift
10

The area of the region bounded by the curves x(1 + y2) = 1 and y2 = 2x is:

  1. 4 - 13
  2. 2 - 13
  3. 2 ( 2 - 13 )
  4. 12 ( 2 - 13 )
JEE Main 2025 (Online) 28th January Evening Shift

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